Optimal. Leaf size=155 \[ -\frac {\tanh ^{-1}\left (\frac {2 a-b+(b-2 c) \tan ^2(d+e x)}{2 \sqrt {a-b+c} \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\right )}{2 (a-b+c)^{3/2} e}+\frac {b^2-2 a c-b c+(b-2 c) c \tan ^2(d+e x)}{(a-b+c) \left (b^2-4 a c\right ) e \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}} \]
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Rubi [A]
time = 0.15, antiderivative size = 155, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 33, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {3781, 1261,
754, 12, 738, 212} \begin {gather*} \frac {-2 a c+b^2+c (b-2 c) \tan ^2(d+e x)-b c}{e (a-b+c) \left (b^2-4 a c\right ) \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}-\frac {\tanh ^{-1}\left (\frac {2 a+(b-2 c) \tan ^2(d+e x)-b}{2 \sqrt {a-b+c} \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\right )}{2 e (a-b+c)^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 212
Rule 738
Rule 754
Rule 1261
Rule 3781
Rubi steps
\begin {align*} \int \frac {\tan (d+e x)}{\left (a+b \tan ^2(d+e x)+c \tan ^4(d+e x)\right )^{3/2}} \, dx &=\frac {\text {Subst}\left (\int \frac {x}{\left (1+x^2\right ) \left (a+b x^2+c x^4\right )^{3/2}} \, dx,x,\tan (d+e x)\right )}{e}\\ &=\frac {\text {Subst}\left (\int \frac {1}{(1+x) \left (a+b x+c x^2\right )^{3/2}} \, dx,x,\tan ^2(d+e x)\right )}{2 e}\\ &=\frac {b^2-2 a c-b c+(b-2 c) c \tan ^2(d+e x)}{(a-b+c) \left (b^2-4 a c\right ) e \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}-\frac {\text {Subst}\left (\int \frac {-\frac {b^2}{2}+2 a c}{(1+x) \sqrt {a+b x+c x^2}} \, dx,x,\tan ^2(d+e x)\right )}{(a-b+c) \left (b^2-4 a c\right ) e}\\ &=\frac {b^2-2 a c-b c+(b-2 c) c \tan ^2(d+e x)}{(a-b+c) \left (b^2-4 a c\right ) e \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}+\frac {\text {Subst}\left (\int \frac {1}{(1+x) \sqrt {a+b x+c x^2}} \, dx,x,\tan ^2(d+e x)\right )}{2 (a-b+c) e}\\ &=\frac {b^2-2 a c-b c+(b-2 c) c \tan ^2(d+e x)}{(a-b+c) \left (b^2-4 a c\right ) e \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}-\frac {\text {Subst}\left (\int \frac {1}{4 a-4 b+4 c-x^2} \, dx,x,\frac {2 a-b-(-b+2 c) \tan ^2(d+e x)}{\sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\right )}{(a-b+c) e}\\ &=-\frac {\tanh ^{-1}\left (\frac {2 a-b+(b-2 c) \tan ^2(d+e x)}{2 \sqrt {a-b+c} \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\right )}{2 (a-b+c)^{3/2} e}+\frac {b^2-2 a c-b c+(b-2 c) c \tan ^2(d+e x)}{(a-b+c) \left (b^2-4 a c\right ) e \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\\ \end {align*}
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Mathematica [A]
time = 3.11, size = 156, normalized size = 1.01 \begin {gather*} -\frac {\frac {\tanh ^{-1}\left (\frac {2 a-b+(b-2 c) \tan ^2(d+e x)}{2 \sqrt {a-b+c} \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}\right )}{(a-b+c)^{3/2}}+\frac {2 \left (-b^2+2 a c+b c-(b-2 c) c \tan ^2(d+e x)\right )}{(a-b+c) \left (b^2-4 a c\right ) \sqrt {a+b \tan ^2(d+e x)+c \tan ^4(d+e x)}}}{2 e} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(405\) vs.
\(2(143)=286\).
time = 0.19, size = 406, normalized size = 2.62
method | result | size |
derivativedivides | \(\frac {\frac {2 c \ln \left (\frac {2 a -2 b +2 c +\left (b -2 c \right ) \left (1+\tan ^{2}\left (e x +d \right )\right )+2 \sqrt {a -b +c}\, \sqrt {c \left (1+\tan ^{2}\left (e x +d \right )\right )^{2}+\left (b -2 c \right ) \left (1+\tan ^{2}\left (e x +d \right )\right )+a -b +c}}{1+\tan ^{2}\left (e x +d \right )}\right )}{\left (\sqrt {-4 a c +b^{2}}-b +2 c \right ) \left (\sqrt {-4 a c +b^{2}}+b -2 c \right ) \sqrt {a -b +c}}+\frac {2 c \sqrt {c \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )^{2}-\sqrt {-4 a c +b^{2}}\, \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{\left (\sqrt {-4 a c +b^{2}}+b -2 c \right ) \left (-4 a c +b^{2}\right ) \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}-\frac {2 c \sqrt {c \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )^{2}+\sqrt {-4 a c +b^{2}}\, \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{\left (\sqrt {-4 a c +b^{2}}-b +2 c \right ) \left (-4 a c +b^{2}\right ) \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{e}\) | \(406\) |
default | \(\frac {\frac {2 c \ln \left (\frac {2 a -2 b +2 c +\left (b -2 c \right ) \left (1+\tan ^{2}\left (e x +d \right )\right )+2 \sqrt {a -b +c}\, \sqrt {c \left (1+\tan ^{2}\left (e x +d \right )\right )^{2}+\left (b -2 c \right ) \left (1+\tan ^{2}\left (e x +d \right )\right )+a -b +c}}{1+\tan ^{2}\left (e x +d \right )}\right )}{\left (\sqrt {-4 a c +b^{2}}-b +2 c \right ) \left (\sqrt {-4 a c +b^{2}}+b -2 c \right ) \sqrt {a -b +c}}+\frac {2 c \sqrt {c \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )^{2}-\sqrt {-4 a c +b^{2}}\, \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{\left (\sqrt {-4 a c +b^{2}}+b -2 c \right ) \left (-4 a c +b^{2}\right ) \left (\tan ^{2}\left (e x +d \right )+\frac {b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}-\frac {2 c \sqrt {c \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )^{2}+\sqrt {-4 a c +b^{2}}\, \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{\left (\sqrt {-4 a c +b^{2}}-b +2 c \right ) \left (-4 a c +b^{2}\right ) \left (\tan ^{2}\left (e x +d \right )-\frac {-b +\sqrt {-4 a c +b^{2}}}{2 c}\right )}}{e}\) | \(406\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 546 vs.
\(2 (147) = 294\).
time = 6.06, size = 1131, normalized size = 7.30 \begin {gather*} \left [-\frac {{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} \tan \left (x e + d\right )^{4} + a b^{2} - 4 \, a^{2} c + {\left (b^{3} - 4 \, a b c\right )} \tan \left (x e + d\right )^{2}\right )} \sqrt {a - b + c} \log \left (\frac {{\left (b^{2} + 4 \, {\left (a - 2 \, b\right )} c + 8 \, c^{2}\right )} \tan \left (x e + d\right )^{4} + 2 \, {\left (4 \, a b - 3 \, b^{2} - 4 \, {\left (a - b\right )} c\right )} \tan \left (x e + d\right )^{2} - 4 \, \sqrt {c \tan \left (x e + d\right )^{4} + b \tan \left (x e + d\right )^{2} + a} {\left ({\left (b - 2 \, c\right )} \tan \left (x e + d\right )^{2} + 2 \, a - b\right )} \sqrt {a - b + c} + 8 \, a^{2} - 8 \, a b + b^{2} + 4 \, a c}{\tan \left (x e + d\right )^{4} + 2 \, \tan \left (x e + d\right )^{2} + 1}\right ) + 4 \, \sqrt {c \tan \left (x e + d\right )^{4} + b \tan \left (x e + d\right )^{2} + a} {\left (a b^{2} - b^{3} - {\left (2 \, a + b\right )} c^{2} - {\left ({\left (2 \, a - 3 \, b\right )} c^{2} + 2 \, c^{3} - {\left (a b - b^{2}\right )} c\right )} \tan \left (x e + d\right )^{2} - {\left (2 \, a^{2} - a b - 2 \, b^{2}\right )} c\right )}}{4 \, {\left ({\left (4 \, a c^{4} + {\left (8 \, a^{2} - 8 \, a b - b^{2}\right )} c^{3} + 2 \, {\left (2 \, a^{3} - 4 \, a^{2} b + a b^{2} + b^{3}\right )} c^{2} - {\left (a^{2} b^{2} - 2 \, a b^{3} + b^{4}\right )} c\right )} e \tan \left (x e + d\right )^{4} - {\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5} - 4 \, a b c^{3} - {\left (8 \, a^{2} b - 8 \, a b^{2} - b^{3}\right )} c^{2} - 2 \, {\left (2 \, a^{3} b - 4 \, a^{2} b^{2} + a b^{3} + b^{4}\right )} c\right )} e \tan \left (x e + d\right )^{2} - {\left (a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} - 4 \, a^{2} c^{3} - {\left (8 \, a^{3} - 8 \, a^{2} b - a b^{2}\right )} c^{2} - 2 \, {\left (2 \, a^{4} - 4 \, a^{3} b + a^{2} b^{2} + a b^{3}\right )} c\right )} e\right )}}, \frac {{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} \tan \left (x e + d\right )^{4} + a b^{2} - 4 \, a^{2} c + {\left (b^{3} - 4 \, a b c\right )} \tan \left (x e + d\right )^{2}\right )} \sqrt {-a + b - c} \arctan \left (-\frac {\sqrt {c \tan \left (x e + d\right )^{4} + b \tan \left (x e + d\right )^{2} + a} {\left ({\left (b - 2 \, c\right )} \tan \left (x e + d\right )^{2} + 2 \, a - b\right )} \sqrt {-a + b - c}}{2 \, {\left ({\left ({\left (a - b\right )} c + c^{2}\right )} \tan \left (x e + d\right )^{4} + {\left (a b - b^{2} + b c\right )} \tan \left (x e + d\right )^{2} + a^{2} - a b + a c\right )}}\right ) - 2 \, \sqrt {c \tan \left (x e + d\right )^{4} + b \tan \left (x e + d\right )^{2} + a} {\left (a b^{2} - b^{3} - {\left (2 \, a + b\right )} c^{2} - {\left ({\left (2 \, a - 3 \, b\right )} c^{2} + 2 \, c^{3} - {\left (a b - b^{2}\right )} c\right )} \tan \left (x e + d\right )^{2} - {\left (2 \, a^{2} - a b - 2 \, b^{2}\right )} c\right )}}{2 \, {\left ({\left (4 \, a c^{4} + {\left (8 \, a^{2} - 8 \, a b - b^{2}\right )} c^{3} + 2 \, {\left (2 \, a^{3} - 4 \, a^{2} b + a b^{2} + b^{3}\right )} c^{2} - {\left (a^{2} b^{2} - 2 \, a b^{3} + b^{4}\right )} c\right )} e \tan \left (x e + d\right )^{4} - {\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5} - 4 \, a b c^{3} - {\left (8 \, a^{2} b - 8 \, a b^{2} - b^{3}\right )} c^{2} - 2 \, {\left (2 \, a^{3} b - 4 \, a^{2} b^{2} + a b^{3} + b^{4}\right )} c\right )} e \tan \left (x e + d\right )^{2} - {\left (a^{3} b^{2} - 2 \, a^{2} b^{3} + a b^{4} - 4 \, a^{2} c^{3} - {\left (8 \, a^{3} - 8 \, a^{2} b - a b^{2}\right )} c^{2} - 2 \, {\left (2 \, a^{4} - 4 \, a^{3} b + a^{2} b^{2} + a b^{3}\right )} c\right )} e\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\tan {\left (d + e x \right )}}{\left (a + b \tan ^{2}{\left (d + e x \right )} + c \tan ^{4}{\left (d + e x \right )}\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\mathrm {tan}\left (d+e\,x\right )}{{\left (c\,{\mathrm {tan}\left (d+e\,x\right )}^4+b\,{\mathrm {tan}\left (d+e\,x\right )}^2+a\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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